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Support CenterKnowledge Base ArticlesCode-check of bolts and preloaded bolts according to Chinese standard
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Code-check of bolts and preloaded bolts according to Australian standards
Code-check of bolts and preloaded bolts according to Chinese standard
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Code-check of preloaded bolts according to Indian standards
Code-check of bolts and preloaded bolts according to Russian standards
The forces in bolts, including prying forces, are determined by finite element analysis. The bolt resistances are checked by GB 50017. Structural design of bolted steel connections.
Connection designSteelKnowledge baseConnectionCBFEM

Code-check of bolts and preloaded bolts according to Chinese standard

This article is also available in
ENCZDEESFRITPTNLHUROKRPLTHTRVIZH

Bolts

Bolts are checked according to GB 50017, Cl. 11.4. The tensile and shear force in each bolt is determined by finite element analysis. Prying forces are determined by finite element analysis and taken into account. Each shear plane is checked individually. The plate in the bearing is checked against the sum of shear forces at nearby planes.

Design tensile and shear strengths of a bolt; fub[MPa] – ultimate strength of a bolt; derived from Table 4.4.6

fubf_{ub}fub​ [MPa]ftbf_t^bftb​fvbf_v^bfvb​
fub≤400f_{ub} \le 400fub​≤4000.425⋅fub0.425 \cdot f_{ub}0.425⋅fub​0.35⋅fub0.35 \cdot f_{ub}0.35⋅fub​
400<fub<830400<f_{ub}<830400<fub​<8300.42⋅fub0.42 \cdot f_{ub}0.42⋅fub​0.38⋅fub0.38 \cdot f_{ub}0.38⋅fub​
830≤fub830 \le f_{ub}830≤fub​40/83⋅fub40/83 \cdot f_{ub}40/83⋅fub​32/83⋅fub32/83 \cdot f_{ub}32/83⋅fub​

Bolt in tension

A bolt subject to a tensile force is designed according to Cl. 11.4.1.2 and shall satisfy:

Nt≤Ntb=As⋅ftbN_t \le N_t^b = A_s \cdot f_t^bNt​≤Ntb​=As​⋅ftb​

where:

  • Nt – tensile force in a bolt
  • Ntb – design tension capacity
  • As=πde24A_s = \frac{\pi d_e^2}{4}As​=4πde2​​ – tensile stress area of a bolt
  • de – effective diameter of a bolt at threaded section
  • ftb – design tensile strength of a bolt

Bolts in shear

A bolt subject to a shear force is designed according to Cl. 11.4.1.1 and shall satisfy:

Nv≤Nvb=Ag⋅fvbN_v \le N_v^b = A_g \cdot f_v^bNv​≤Nvb​=Ag​⋅fvb​

where:

  • Nv – shear force in a bolt in investigated plane
  • Ag=πd24A_g = \frac{\pi d^2}{4}Ag​=4πd2​ – gross cross-section area of a bolt
  • d – nominal diameter of a bolt
  • fvb – design shear strength of a bolt

Each shear plane is checked individually, i.e. number of shear planes nv = 1.

Bolts in combined tension and shear

A bolt loaded in shear and tensile forces at the same time is designed according to Cl. 11.4.1.3 and shall satisfy:

(NvNvb)2+(NtNtb)2≤1.0\sqrt{\left ( \frac{N_v}{N_v^b} \right ) ^2 + \left ( \frac{N_t}{N_t^b} \right ) ^2} \le 1.0(Nvb​Nv​​)2+(Ntb​Nt​​)2​≤1.0

where:

  • Nv – shear force in a bolt in investigated plane
  • Nt – tensile force in a bolt
  • Nvb – design shear resistance of a bolt
  • Ntb – design tensile resistance of a bolt

Bolts in bearing

A plate subject to a bearing force due to a bolt in shear is designed according to Cl. 11.4.1.1 and shall satisfy:

Nv≤Ncb=d⋅t⋅fcbN_v \le N_c^b = d\cdot t \cdot f_c^bNv​≤Ncb​=d⋅t⋅fcb​

where:

  • Nv – shear force in acting on a plate; vector sum of shear forces in nearby planes
  • d – nominal bolt diameter
  • t – plate thickness
  • fcb – design bearing strength of a plate

Design bearing strength of a plate; fu – ultimate strength of a plate; derived from Table 4.4.6

Preloaded bolts

High strength bolt in friction type joint is designed according to Cl. 11.4.2.

Preloaded bolts in tension

The tensile resistance of a preloaded bolt is determined as:

Nt≤Ntb=0.8⋅PN_t \le N_t^b = 0.8 \cdot PNt​≤Ntb​=0.8⋅P

where:

  • Nt – tensile force in a bolt
  • Ntb – design tension capacity
  • P – pretension of a high strength bolt – Table 11.4.2-2

Table 11.4.2-2 – pretension of a high strength bolt P [kN]

Bolt gradeM16M20M22M24M27M30
8.880125150175230280
10.9100155190225290355

A preloaded bolt which is not in Table 11.4.2-2 subject to a tensile force is designed according to Cl. 11.4.1.2 and shall satisfy:

Nt≤Ntb=As⋅ftbN_t \le N_t^b = A_s \cdot f_t^bNt​≤Ntb​=As​⋅ftb​

where:

  • Nt – tensile force in a bolt
  • Ntb – design tension capacity
  • As=πde24A_s = \frac{\pi d_e^2}{4}As​=4πde2​​ – tensile stress area of a bolt
  • de – effective diameter of a bolt at threaded section
  • ftb – design tensile strength of a bolt

Preloaded bolts in shear

The design resistance of a preloaded bolt in shear is determined according to Cl. 11.4.2.1:

Nv≤Nvb=0.9kμPN_v \le N_v^b = 0.9 k \mu PNv​≤Nvb​=0.9kμP

where:

  • Nv – shear force in investigated plane
  • Nvb – design shear resistance of a bolt
  • k – factor for bolt holes; k = 1 for normal holes, k = 0.85 for oversized holes, k = 0.6 for slotted holes
  • μ – slip coefficient at friction interface taken from Table 11.4.2-1; editable in Code setup
  • P = Ntb / 0.8 – pretension of a high strength bolt for bolts which are not in Table 11.4.2-2

Each shear plane is checked individually, i.e. number of shear planes nf = 1.

Preloaded bolts in combined tension and shear

A bolt loaded in shear and tensile forces at the same time is designed according to Cl. 11.4.2.3 and shall satisfy:

NvNvb+NtNtb≤1.0\frac{N_v}{N_v^b} + \frac{N_t}{N_t^b} \le 1.0Nvb​Nv​​+Ntb​Nt​​≤1.0

where:

  • Nv – shear force in investigated plane
  • Nt – tensile force in a bolt
  • Nvb – design shear resistance of a bolt
  • Ntb – design tensile resistance of a bolt

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